4x^2+100=3

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Solution for 4x^2+100=3 equation: 



4x^2+100=3

We move all terms to the left:

4x^2+100-(3)=0

We add all the numbers together, and all the variables

4x^2+97=0

a = 4; b = 0; c = +97;
Δ = b2-4ac
Δ = 02-4·4·97
Δ = -1552
Delta is less than zero, so there is no solution for the equation

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